A sample of 4 different calculators is randomly selected from a group containing 14 that are defective and 34 that have no defects. What is the probability that a sample of four calculators from this batch will contain no defective calculators

below

Step-by-step explanation:

P (at least one defective) = 1 - P(all calculators work)

=  

1

−

(

30

46

×

29

45

×

28

44

×

27

43

)

=

1

−

1827

10879

=  

9052

10879

≈

0.832

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/

it is contrapositive

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