Mr. Hamilton decorates his U. S. History classroom by putting up pictures of the presidents. The wall is 9.75 feet long. In the center, there is a window that is 5 ¾ ​ feet long. Each president's picture is 6 inches wide.

4. How would your answer change if the pictures were 10 inches wide? Explain.

8

Step-by-step explanation:

Given

Required

Determine the number of pictures

First, we need to calculate the length of the available space

This is calculated by subtracting the width of the window from the width of the wall.

Convert fraction to decimal

Since, the pictures are placed side by side.

This means that, there's no empty space between them.

Number of pictures is:

Convert feet to inches

The number of pictures changes from 8 to 4.

Step-by-step explanation:

I assume the first question was the number of pictures that could be placed when the pictures are 6 inches wide.

Let's first answer the first question.

Wall length: 9.75 ft

Window: 5¾ ft = 5.75 ft

Available wall space for pictures:

9.75 ft - 5.75 ft = 4 ft

Now we convert 4 ft to inches.

1 ft = 12 inches

4 ft = 4 * 12 inches = 48 inches

There is 48 inches of wall space to place pictures that measure 6 inches each.

48 inches / 6 inches = 8

Originally, there is room for 8 pictures.

Question 4.

Each picture is 10 inches wide.

There is still 48 inches of wall space for the pictures.

48 inches / 10 inches = 4.8

There is room for 4.8 pictures. Since Mr. Hamilton will place only whole picture, he can only place 4 pictures now.

The number of pictures changes from 8 to 4.

can i see the following ?

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)