I need help with the incorrect ones please

73.6

61.824

.2776

2.3

1.342

.4129

*note* I had trouble reading the standard deviation of the second part, so if it's not 3 then leave a comment and i will fix it*

Step-by-step explanation:

1.)

the mean would be something like 460*.16= 73.6

The variance should be 460*.16(1-.16)= 61.824 which means the standard deviation is √61.824= 7.863

for p to be less than .15 it would have to be less than .15*460= 69

(69-73.6)/7.863= -.59 which has a probability of .2776

2.)

the mean is 2.3

I am not sure if the standard deviation is 3 or .3 (picture is kind of blurry)

I am thinking that it's three which would mean that the standard deviation would be √(3²*(1/5))= 1.342

(2-2.3)/1.342= -.22 = .4129

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204