A consumer group wishes to estimate the proportion of adult Twitter users that get at least some news on Twitter. A poll is conducted and it is found that from a SRS of 1251 adult Twitter users, 641 of them get at least some news on Twitter. You will be finding a 90% confidence interval for the fraction of adult Twitter users who get some news on Twitter. Required:
a. Check that the normality assumptions are met?
b. What is the 90% confidence interval for the proportion of adult Twitter users that get at least some news on Twitter. Round to 4 decimal places.
c. Interpret the confidence interval obtained.

y -5 = (-1/4)(x + 8)

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

c.the first excerpt shows their expectations about the camp, and the second shows the reality of their circumstances

is the answer this is because first they talk about what is expected of the camp but in the second excerpt they get a harsh awakening to the true realities of the camp.

hope this

i would appreciate brainliest : )