For each of the following equations, determine whether y is a function of x. x= -7y^2
b. x = 1/4y
c. y^2 = 4x +9
d. y= 5x +8

9514 1404 393

  a) not a function

  b) is a function

  c) not a function

  d) is a function

Step-by-step explanation:

If the graph passes the "vertical line test," then the relation is a function.

Choices B and D are linear equations. Their graph is a straight line, so each x-value corresponds to exactly one y-value. (Every non-vertical line passes the vertical line test.)

Choices A and C are equations of parabolas that open horizontally. It is easy to draw a vertical line that intersects the graph twice, so these relations fail the vertical line test.

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  B, D -- functions

  A, C -- not functions

16 would be your answer

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7