What is the solution to the system of equations below?

2x+3y=6
x-3y=9

Step-by-step explanation:

2x + 3y = 6

2x = 6-3y

x = (6-3y)/2

x - 3y = 9

(6-3y)/2 -3y = 9

(6-3y)/2 -6y/2 = 9

(6-9y)/2 = 9

6 - 9y = 9×2

-9y = 18-6

y = 12/-9

y = -4/3

2x + 3y = 6

2x + 3(-4/3) = 6

2x -4 = 6

2x = 6+4

2x = 10

x = 10/2

x = 5

Therefore x = 5 and y = (-4/3)

I used subsitution method

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x = 5; y = -4/3

Step-by-step explanation:

One equation has 3y. The other equation has -3y. Add the equations to eliminate y and solve for x.

     2x + 3y = 6

(+)     x - 3y = 9

      3x        = 15

x = 5

2x + 3y = 6

2(5) + 3y = 6

3y + 10 = 6

3y = -4

y = -4/3

x = 5; y = -4/3

42

step-by-step explanation:

256/6=42

126 maybe. sorry