WILL GIVE BRAINLIEST AND 20 POINTS! SHOW WORK! How many different 6-digit phone numbers do not contain the digit 6? Assume that any digit in the phone number can be any of the remaining numbers. Use the Multiplication Principle of Counting to solve the problem.

Step-by-step explanation:

We don't know if the number can start with a 0 or 1. Since we don't know, I will assume the number can start with either. The restriction is on 6s.

The way this is worded, I'm not sure if the digits can be repeated or not. It sounds like they can.

9 * 9 * 9 * 9 * 9 * 9 = 531441

If you are not allowed to repeat and no digit is a 6 then you get

9 *8 * 7 * 6 * 5*4 = 60480

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°