The cost of plastering in 4 walls of a room whose length is three times its height as wellas twice its breadth at Rs 5per m^2 is Rs 720. What will be the cost of the carpenting the floor of the room at Rs 250per m^2​

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Step-by-step explanation:

Say the height of the room is X metres. So the length is 3X, and the breadth is length/2, or 3X/2.

The area of the 4 walls is then 3x^2 + 3X^2 + 3X^2/2 +3X^2/2 = 9X^2

If the cost of plastering is R5/sq m, then 9X^2 * 5 = 720

Solving this gives X = 4 m - a rather high ceiling

The floor area is then (3*4) * (3*4/2) = 72 sq m

Carpeting is then 250*72 = R18000

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

no not all of them.

step-by-step explanation:

some of them have a square base.