The curve y=(k-6)x^2-8x+k cuts the x-axis at two points and has a minimum point. Find the range of values of k.

Hello,

 -2 < k < 8

Step-by-step explanation:

As there are 2 roots: Δ>0

As there is a mininum, k-6 <0 ==> k<6,

minimum :y'=0 ==> (k-6)*2x-8=0 ==> x=4/(k-6)

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

answerthe vertex form

step-by-step explanation: