What is 7a expressed as a-p(x+q)^2? Ill give brainliest to first correct answer

9 - 2(x+1.5)²

Step-by-step explanation:

To solve this, we can apply a process called "Completing the Square". To do this, we can first separate the 9 and add that back later, leaving us with

-6x-2x² = -2x²-6x

Then, we can factor out the number that attaches to the x² (its coefficient, which is -2 in this case) to get

-2 (x²+3x)

After that, we can divide the coefficient of the x by 2, so 3/2 = 1.5 in this case, and representing that as q, we can write our expression as

-2 (x+q)². Plugging 1.5 in for q in this case, we get

-2(x+1.5)²

Now, we need to reconcile this with our original expression of

9-6x-2x². To do this, we can first expand -2(x+1.5)² to get

-2(x²+3x+2.25) = -2x²-6x-4.5. We now have

-2x²-6x-4.5 and want to turn it into

9-6x-2x² = -2x²-6x+9

To do this, we can add 13.5 to -2x²-6x-4.5, so our expression is

-2x²-6x-4.5 + 13.5

= -2(x+1.5)² + 9

= 9 - 2(x+1.5)²

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: