Triangle CDE is similar to triangle FGH. Find the measure of side HF. Round your answer to the nearest tenth if necessary.

HF = 11.0

Step-by-step explanation:

We can use a ratio to solve

ED        EC

=

HG       HF

23       36

=

7         HF

Using cross products

23 HF = 36*7

23 HF = 252

Divide by 23

HF = 252/23

HF =10.95652

To the nearest tenth

HF = 11.0

hi there!

the answer will be d: 2

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.