A rectangluar swimming pool 25 feet long, 15 feet wide, and 7 feet deep is filled with water to a depth of 6 feet. The weight density of water is 62.4 lb ft 3 lb/ft^3. Calculate the work required to pump all of the water out over the top. ft-lb

9514 1404 393

  491,400 ft·lb

Step-by-step explanation:

The mass of the water is ...

  M = Vρ = LWHρ = (25 ft)(15 ft)(7 ft)(62.4 lb/ft³) = 163,800 lb

The average depth is 3 ft, so the work required is equivalent to that required to raise this mass 3 ft.

  W = (3 ft)(163,800 lb) = 491,400 ft·lb

b.my answer is b.

brainliest

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)