What is the distance between (1, 9) and (1, -4)? Use the distance formula. D=(x2-x1)2+(y2-y1)2

D. 13

Step-by-step explanation:

You just have to plug in numbers then solve.

(1,9) and (1,-4). Every coordinate is placed as (x,y)

(1,9) is labeled as (x1, y1)

(1,-4) is labeled as (x2,y2)

Now plug in the numbers.

d= Square root of (1-1)^2 + (-4-9)^2

d= Square root of 1^2 +-13^2

d= Square root of 1+169

d= Square root of 170

d= 13.04

Rounded to a whole number, the answer is 13

D

Step-by-step explanation:

you have to substitute the values in the distance formula,in this case x2 is 1,x1 is 1,y2 is -4 and y1 is 9

d=√(x2-x1)²+(y2-y1)²

=√(1-1)²+(-4-9)²

=√(0)²+(-13)²

=√169

=13

I hope this helps

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

168

step-by-step explanation:

i am pretty sure that the answer is 168