Two boxes labeled A and B are full of tickets numbered either 00 or 11 for classifying and counting. (The sum of the draws equals the number of 1's in the draws and the average of the draws equals the proportion of 1's in the draws.) We know that in Box A, 36% of the tickets are labeled 11 . We also know that in Box B, 10% of the tickets are labeled 11 . We will draw at random with replacement 400 times from Box A. Independently, we will draw at random with replacement 400 times from Box B. From Box A: the sum of the 400 draws expected value equal:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

you can download it here

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct