The triangular prism has a length of 40 centimeters, an end base of 5 centimeters, and an end height of 7 centimeters. What is the volume of this prism?

Step-by-step explanation:

volume of triangular prism= area of cross section *length

volume of triangular prism= area of cross section *lengthv=(1/2bh)l

volume of triangular prism= area of cross section *lengthv=(1/2bh)lv=?,b=5,h=40

volume of triangular prism= area of cross section *lengthv=(1/2bh)lv=?,b=5,h=40 =(1/2*5*7)40

volume of triangular prism= area of cross section *lengthv=(1/2bh)lv=?,b=5,h=40 =(1/2*5*7)40 =(35/2)40

=17.5*40

=700cm³

The volume of triangular prism is 700cm³

Step-by-step explanation:

Good luck

x = 25/2304

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.