In a plan for area codes, the first digit could be any number from 2 through 8, the second digit was either 0 or 3, and the third digit could be any number except 0. With this plan, how many different area codes were possible?

Ais the correct answer

2(10 - 13x) + 9x = -34x + 6020 - 26x + 9x = -34x + distributive property-17x = -34x + subtraction property (subtracted 20 from both sides)17x = addition property (added 34x to both sides)x = 40/ division property (divided both sides by 17)

The answer is c, because you subtract 18, and then divide by -3 and flip the sign.