1. Determine the set of each of the following equations for 0° ≤ x 360° or 0° ≤ t ≤ 360° a) sin 2 x°= 1/2√2

2. find all the solution in the interval 0° ≤ z ≤ 360° of the following equation
sin 3 z = - 0,42

Please help Me​

a).

since sine is in the 2nd quadrant, other angle = 180° - x:

we must make two rotations since it's a double angle:

divide each angle by 2:

Answer = {x: x = 22.5°, 67.5°, 112.5°, 157.5°, 247.5, 337.5°}

b).

since ans is negative, we take the quadrants of cosine and tangent:

we make three rotations:

answer is {z : z = 128.3°, 171.7°, 231.7°, 291.7°, 351.7°}

180 square centimeters

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.