A sum of Rs 105 is divided into two parts. if two times the greater part is 15 less than three times the smaller part, find the parts of the sum.

Rs. 39, Rs, 66

Step-by-step explanation:

Let the greater part = x

The smaller part = y

x + y = 105    (I)

     x =  105 - y (II)

Two times the greater part is 15 less than three times the smaller part:

2x -15 = 3y

2x =  3y + 15

2x - 3y = 15  (III)

Substitute x = 105 - y in equation (III)

2*(105 - y) - 3y = 15

2*105 - 2*y - 3y = 15    {distributive property}

210 - 2y - 3y = 15

Combine like terms

210 - 5y = 15

Subtract 210 from both sides

-5y = 15 - 210

-5y = - 195

Divide both sides by -5

y = -195/-5

y = 39

Plug in y = 39 in equation (II)

x = 105 - 39

x = 66

whats the question?

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice