50 POINTS1 Solve 6 over x minus 6 equals the quantity of x over x minus 6, minus six halves. for x and determine if the solution is extraneous or not.

A. x = −6, extraneous

B. x = −6, non-extraneous

C. x = 6, non-extraneous

D, x = 6, extraneous

x = 6, extraneous

Step-by-step explanation:

6/(x - 6) = x/(x - 6) - 6/2

6/(x - 6) = x/(x - 6) - 3

6 = x - 3(x - 6)

6 = x - 3x + 18

-12 = -2x

/-2     /-2

x = 6

When you are substituting x = 6 back into the equation, it makes the denominator = 0, so this is an extraneous solution.

mx+89b(-98)nb

step-by-step explanation:

∈3,600

step-by-step explanation: