{ x | x < 3 or x > 1}
Mathematics, 17.08.2021 02:30 alexkrol30083
Solve (2x < 6) ∩ (x - 5 > -4).
{all real numbers}
{ x | x < 3 or x > 1}
no solution
{ x | 1 < x < 3}
Answers: 2
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Convert the mixed numbers into improper fractions. convert the improper fraction to mixed numbers.
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Determine which postulate or theorem can be used to prove that lmn =nmo
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Solve (2x < 6) ∩ (x - 5 > -4).
{all real numbers}
{ x | x < 3 or x > 1}
{ x | x < 3 or x > 1}
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