Which of the following values are solutions to the inequality 3x+10\ge 2?3x+10≥2? \text{I.}\hspace{2px}-1\hspace{20px }\text{II.}\hspace{2px}3\hspace{20p x}\text{III.}\hspace{2px}-11
I.−1II.3III.−11

\text{None}None
\text{I only}I only
\text{II only}II only
\text{III only}III only
\text{I and II}I and II
\text{I and III}I and III
\text{II and III}II and III
\text{I, II and III}I, II and III

9514 1404 393

  I and II

Step-by-step explanation:

The inequality ...

  3x +10 ≥ 2

has solutions ...

  3x ≥ -8 . . . . . . . . subtract10

  x ≥ -2 2/3 . . . . . divide by 3

Of the answer choices {-1, 3, -11}, the ones that are greater than -2 2/3 are ...

  -1, 3 . . . . . . I and II only

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2