What are the x- and y-intercepts of g(x) = 4 - X2?

g(x) = 4 - x^2

at x-intercept, y=0

0=4-x^2

x^2=4

x = ± 2

=> two x- intercepts, (-2,0) and (2,0)

at y-intercept, x = 0

g(x) = y = 4 - 0 = 4

y-intercept = (0,4)

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

the answer is c hope this