The probababilities of Juma, Ali and Musa passing an examination are 3/5 and 1/4 respectively. Find the probability that: a)either juma or Ali will pass b)Both Ali and Musa will pass
c)all the three will fail​

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x

if you get paid hourly because if you get a salary you could work all week and only get paid a certain amount no matter how much you work but if you get paid hourly then you get paid for every minute you worked.

the answer is 24.04 :

step-by-step explanation: