An interger p is two-third of another and their difference is 10.find the two interferes

30 , 20

Step-by-step explanation:

Let the other number  = x

x - p = 10    

Plugin p = (2/3)x in this equation,

Multiply both side by 3

x = 10*3

x = 30

p = 20

30 and 20

Step-by-step explanation:

We have an integer p and another p , their difference is 10 , so

p - p = 10 ( multiply through by 3 to clear the fraction )

3p - 2p = 30 , that is

p = 30

and × 30 = 2 × 10 = 20

The 2 integers are 30 and 20

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

just sum

10 + 10 = 20