F m∠A = m∠B and m∠A + m∠C = m∠D, then
m∠B + m∠C = m∠D. Which property is shown?

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

answer: x=1

step-by-step explanation:

f(x) = g(x)

x - 2 = -1

x = 1

therefore the graph should be a line showing x=1 which is vertical and passes on 1

hope it !