Find the possible formula for the nth term of sequence 7 11 15 9​

7, 11, 15, 19, 23, ... To get the terms in the original sequence, we need to add on 3 to each of the terms in the 4n sequence. Hence, the general formula for the nth term of the original sequence is 4n + 3.

hope this helped!!!

Here,

First term(a) = 7

common difference(d) = 11 - 7

= 4

last term(tn) = ?

Now,

tn = a + (n - 1)*d

or, tn = 7 + (n - 1)*4

or, tn = 7 + 4n - 4

◆tn = 4n + 3

I hope it's help you...

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answer: h

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)