the floor of a room is 12 m long and 6 m wide the floor of this room is to be fitted with tiles of dimension 10 cm x 2 cm what will the total expense in Rupees if the cost of tiling is 5 atile​

Step-by-step explanation:

the price is 5 per tile ?

the area of the rectangular room is

12×6 = 72 m²

each m² has 100×100 = 10000 cm²

so, we have for the total area in cm²

72 × 10000 = 720000 cm²

one tile has 10×2 = 20 cm²

so, how many tiles will we need ?

720000 / 20 = 72000 / 2 = 36000 tiles.

so, if truly 1 tile costs 5 Rupees, then we have

36000 × 5 = 180000 Rupees as total costs.

sure i'm up for it

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.