If the maximum score on a quiz is 120, is it possible to have a mean of 100 after the fifth quiz

i dont think it is possible since you are losing percentage by the fifth time you are taking a quiz so if the max score is 120 it is not possible to still get 100 percent on the fifth try to will lose percent i think you can get 100 percent by the second or third try

Step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

his chances of getting a coin of higher value is 4/19

step-by-step explanation: