a father is 25 years older than his son. Five years ago he was 6 time old as his son was find their presents

the present age of the father be x and the present age of the son be y.

It is given that man is 24 years older than his son that is:

x=y+24

x−y=24(1)

Also, 12 years ago, he was five times as old as his son that is:

(x−12)=5(y−12)

x−12=5y−60

x−5y=−60+12

x−5y=−48(2)

Now subtract equation 1 from equation 2 to eliminate x, because the coefficients of x are same. So, we get

(x−x)+(−5y+y)=−24−48

i.e. −4y=−72

i.e. y=18

Substituting this value of y in (1), we get

x−18=24

i.e. x=24+18=42

Hence, the present age of the father is 42 years and the present age of the son is 18 years.

Step-by-step explanation:

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

2/3

step-by-step explanation: