49q²-70q+25 resolve into fractors​

(7q-5)²

Step-by-step explanation:

= 49q² - 70q + 25

= 49q² -35q -35q + 25

= 7q(7q-5) - 5(7q - 5)

= (7q-5) (7q-5)

= (7q-5)²

CMIIW

Step-by-step explanation:

49q² -70q +25 , rewrite the first two terms as squares

(7q)² -70q + 5² , compare with  a² - 2ab + b² = (a-b)²

    a² - 2ab + b²

(7q)² -2(7q)(5 )+ 5², because 70q = 2*35q = 2*7*5*q

We can see that a = 7q and b=5, therefore

49q² -70q +25 = (7q -5)²

We set the equation equal to 0 to find the roots

7q-5 =0, add 5 to both sides

7q =5 , divide both sides by 7

q = 5/7 ≈ 0.714

the answer is d

step-by-step explanation: