Mathematics, 30.08.2021 05:00 mateoperez496

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b(1)=16
b(n)=b(n−1)+1

Find the 2^{\text{nd}}2
nd
2, start superscript, start text, n, d, end text, end superscript term in the sequence.

Answers: 3

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b(1)=16
b(n)=b(n−1)+1
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⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ b(1)=16 b(n)=b(n−1)+1 ​ Find the 2^{\text{nd}}2 nd 2, start superscript, start text, n, d, end text, end superscript term in the sequence.

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⎩ ⎪
⎪
⎨
⎪
⎪
⎧

b(1)=16
b(n)=b(n−1)+1

Find the 2^{\text{nd}}2
nd
2, start superscript, start text, n, d, end text, end superscript term in the sequence.