What are the vertices of ΔA'B'C produced by T−3, 6 (ΔABC) = ΔA'B'C? The graph with X-coordinate marks -4, -2, 0, 2, 4 and Y-coordinate mark -4, -2, -1, 0, 2, 4. -The triangle ABC with coordinates A at (3, 0), B at (3, -2), C at (0, -3). A. A′(0, 6), B′(0, 4), C′(−3, 3) B. A′(6, 6), B′(6, 4), C′(3, 3) C. A′(0, −6), B′(0, −8), C′(−3, 9) D. A′(6, −6), B′(6, −8), C′(3, 9)

33/100 is what i got

the answer is a. hope this

step-by-step explanation:

the cross section of an object is the shape you get when you cut straight through an object.

thus the cross section of the human hair is a circle. hence the cross sectional area is the area of a circle and area of circle is :

a = 3.14 × r²

we are given that the average width of human hair is = 4 × (1 / 10³) cm.

so the diameter of the circle is = 4 × (1 / 10³) cm.

∴ radius r = (diameter/2) = 2 × (1/10³) cm

now area a = 3.14 × (2 × (1/10³))² cm²

scientific notation is a standard way of writing very large and very small numbers so that they’re easier to both compare and use in computations. to write in scientific notation, follow the form

n × 10 ᵃ

where n is a number between 1 and 10, but not 10 itself, and a is an integer (positive or negative number).

so area can be rewritten in scientific notation as :

⇒ 3.14 × 4 × (1/10⁶)

⇒ 12.56 × 10 ⁻⁶ cm²

⇒1.256 × 10⁻⁷ cm²