What is the equation of the line that passes through the point ( -4, 2) and has a slope of
-2?

The equation is: y = -2x -6

Step-by-step explanation:

We have the slope which is - 2. This the main form of a straight line equation is: y = mx + c

y = y point (2)

m = slope (-2)

x = x point (-4)

c = constant - this you need to work out!

Firstly we arrange the equation: y = mx + c

We substitute or replace what we already know into this equation. It is like building a puzzle and only the last piece is unknown and we are trying to make this last piece fit into this puzzle.

The only thing we don't know is what c equals to. After substituting, we get

y = -2x + c.

We can further substitute x and y which is the point (-4;2), we then get:

2 = - 2(- 4) + C

and by using simple math by taking the

- 2(- 4) (which equals to +8, since multiplying 2 negative numbers give you a positive number) to the other side which becomes negative, will give you c = - 6.

Then sub C into the equation.

Hope this helps. :)

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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step-by-step explanation:

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