When a ball is dropped from a state of rest at time =0, the distance it has traveled after seconds is ()=4.9^2 meters. (a) How far does the ball travel during the time interval [4,4.5]?
When a ball is dropped from a state of rest at time =0, the distance it has traveled after seconds is ()=4.92 meters.
(b) Compute the average velocity over the time interval [4,4.5].
(c) By computing the average velocity over the time intervals [4,4.1], [4,4.01], and [4,4.001], estimate the ball's instantaneous velocity at =4

33

step-by-step explanation: g=6

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

b mark me branliest thx

step-by-step explanation:

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation: