A rocket is shot in the air at an initial velocity of 12 800 miles per hour. If 1 mile is equal to 5 280 feet, then what is the rocket's speed in feet per second, during take-off?

GIVEN,

Initial velocity of the rocket = 12800miles/hour

1 mile = 5280 feet

Initial velocity of the rocket in miles/second = (12800*5280)/60*60 feet/second = 18773.33333...feet/second.

THANK YOU FOR READING.

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.