Find the slope of the line that is parallel to the graph of 2x+3y=5

slope = -

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

2x + 3y = 5 ( subtract 2x from both sides )

3y = - 2x + 5 ( divide terms by 3 )

y = - x + ← in slope- intercept form

with slope m = -

Parallel lines have equal slopes

Then slope of parallel line is -

slope is -2/3

Step-by-step explanation:

General form of a straight line :- y = mx + c

Here , 2x + 3y = 5

3y = -2x + 5

so comparing the given equation with general form we get

and required line is parallel to given line so required slope is -2/3

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: