Two lines L1 and L2 pass through the point of intersection of 2y=x-13 and 3y+x+12=0. L1 passes through p(-4,-7)and L2 is perpendicular to 2x-5y=4.find the acute angle between L1 andL2 ​

This is impossible to answer without the graph from the if you post the graph then we can .

To find the x-intercept, make  y  equal to zero, and solve for  x. to find the y-intercept, make  x  equal to zero, and solve for  y.explanation: y=4x−2x-intercept0=4x−2add  2  to both sides of the equation.2=4xdivide both sides by  4.24=xsimplify.12=xswitch sides.x=12y-intercepty=4(0)−2y=−2