Which shows the correct solution of the equation 1/2a+2/3b=50 when b=30?

a = 15 if a and b are in the numerator and not the denominator

Step-by-step explanation:

Assuming a and b are NOT in the denominator (unclear in the question)

equation is a/2 + 2b/3 = 50 now substitute 30 for b

a/2 + 2(30)/3 = 50 now simplify the second term

a/2 + 20 = 50  subtract 20 from both sides, then multiply both sides by 2 and you will have the value for a

If a and b are in the denominator, see below

1/2a + 2/3b = 50 substitute 30 for b

1/2a + 2/90 = 50 multiply both sides by 90

45/a + 2 = 4500 subtract 2 from both sides

45/a = 4498 now invert both sides

a/45 = 1/4498 and then multiply both sides by 45

a = 45/4498 = ~.01 (I rounded)

a = 15 if a and b are in the numerator and not the denominator

Step-by-step explanation:

Assuming a and b are NOT in the denominator (unclear in the question)

equation is a/2 + 2b/3 = 50 now substitute 30 for b

a/2 + 2(30)/3 = 50 now simplify the second term

a/2 + 20 = 50  subtract 20 from both sides, then multiply both sides by 2 and you will have the value for a

If a and b are in the denominator, see below

1/2a + 2/3b = 50 substitute 30 for b

1/2a + 2/90 = 50 multiply both sides by 90

45/a + 2 = 4500 subtract 2 from both sides

45/a = 4498 now invert both sides

a/45 = 1/4498 and then multiply both sides by 45

a = 45/4498 = ~.01 (I rounded)

its d. the first coordintaes are 10,32

step-by-step explanation: