What is 5r^(2)-14r+ 8 =
in general trinomial

STEP

1

:

Equation at the end of step 1

(5r2 - 14r) + 8

Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -14 .

-40 + -1 = -41

-20 + -2 = -22

-10 + -4 = -14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -4

5r2 - 10r - 4r - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

5r • (r-2)

Add up the last 2 terms, pulling out common factors :

4 • (r-2)

Step-5 : Add up the four terms of step 4 :

(5r-4) • (r-2)

Which is the desired factorization

Final result :

(r - 2) • (5r -4)

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.