The sum of 2112 + 2212 + 2312 when divided by 4, leaves no remainder. What will be the remainder when the sum of 2113 + 2213 + 2312 is divided by 4?

Step-by-step explanation:

2112 + 2212 + 2312 / 4 leaves no remainder, as already the individual numbers could be divided by 4 without remainder.

2113 = 2112 + 1

2213 = 2212 + 1

so, we get a remainder of +1 and +1 for these 2 numbers, so we get in total a remainder of +2.

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

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22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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