Which conditional completes the law of syllogism? if p → q and are true statements, then p → r is a true statement.

The law of syllogism is similar to the transitive property:

a->b and b->c  => a->c

So

p->q and => p->r

will require the second proposition to be q->r, which completes the syllogism

p-> and q->r => p->r

7

step-by-step explanation:

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value