Ms. Jones is paid $1500 per week but is fined $150 each day she is late to work. Ms. Jones wants to make at least $5,000 over the next five weeks so she can take a vacation. Over the next four weeks, what
is the maximum number of days she can be late to work and still reach her goal of making at least $5000?

6 days Please at least say thanks and leave a good review

Step-by-step explanation:

1500 per week works 4 weeks

maximum would be 6000

if she is late 6 days she loses 900 dollars and would be left with 5100

if she is late 7 days  she loses 1050 and would be left with 4950 so she can be late no more than 6 days

Seven times.

Step-by-step explanation:

You divide 5000 by 1500 to see how many weeks Ms. Jones needs to get $5000. Then, subtract 150 until you get 5,090. You subtracted 7 times, so she can only be late for work 7 times.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)