The vertices of AABC are A(-4,5), B(-2,3), and C(-3,3). If AABC is reflected across the line y = 1 to produce the image AA'B'C', find the coordinates of the vertex C'
The coordinates of C' after a reflection across the line y = 1 are 1
(Type an ordered pair)

$12. that is my answer.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

part a: 1.08

part b: 27.59

3/20

step-by-step explanation:

well, there are 20 outcomes, and 3 of them you want. so, 3/20