Write the equation of a line containing the point (4, -1) and having slope 12. Group of answer choices

y=12x+3.5

y=12x−3

y=12x−1

y = 12x - 49

Step-by-step explanation:

Since we are given the slope(m) and a point (x,y), we can use the point-slope equation to solve for the equation of the line.

y - y = m(x - x)

Plug in the given numbers

y - -1 = 12(x - 4)

Minus a negative becomes a positive

y + 1 = 12(x - 4)

y + 1 = 12x - 48

y = 12x - 49

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17