Which of the following equations have exactly one solution? Choose all answers that apply:

A
2x-31=2x-312x−31=2x−312, x, minus, 31, equals, 2, x, minus, 31

B
2x-31=-2x-312x−31=−2x−312, x, minus, 31, equals, minus, 2, x, minus, 31

(Choice C)
2x+31=2x-312x+31=2x−312, x, plus, 31, equals, 2, x, minus, 31

(Choice D)
2x-2=2x-312x−2=2x−31

answer: first option i.e. 'a' is correct.

step-by-step explanation:

since we have given that

number of minutes to wrap a small gift box = 4 minutes

we need to find the number of gifts to be wrapped in 5 minutes

since there is a direct variation, as the number of minutes will increase with   number of gifts to be wrapped.

so, let the number of gifts to be wrapped in 5 minutes be x.

so, it becomes,

hence, first option 'a'   is correct.

there is no graph so i cant sorry

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0