What is the equation of the line that passes through
(-2, 4) and (2, 7)?

Step-by-step explanation:

Hi there!

We want to find the equation of the line that passes through (-2, 4) and (2, 7).

The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept.

First, let's find the slope of the line.

The slope, calculated from two points is given as the formula , where and are points.

We have two points, which is needed to find the slope, but let's label their values to avoid confusion.

Now substitute those values into the formula.

m=

m=

Simplify

m=

m=

So the slope of the line is .

Substitute that value as m in y=mx+b

y=

Now we need to find b

As the equation passes through both (-2, 4) and (2, 7), we can substitute the values of either one of them in the equation to solve for b

Taking (-2, 4) for example,

Substitute -2 as x and 4 as y:

4=

Multiply

4=+b

Add -3/2 to both sides

Substitute that value into the equation

y=

Hope this helps!

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

don't report but were is the digram

step-by-step explanation: