Rearrange the steps into the order you would follow to create a copy of CAB. Place the first step at the top and the last step at the bottom 1.Place the compass point at A. Draw an are that intersects both rays of ZA. Label the points of intersection B and C.

2.Without changing the setting, place the compass point at Y and draw an arc. Label the point Z where the two arcs intersect.

3.Use a straightedge to draw a ray with endpoint X.

4.Without changing the setting, place the compass point at X and draw an are intersecting the ray. Mark the point Y at the intersection.

5.Use a straightedge to draw XZ.

6. Mark a point X

7. Place the compass point at C and open the compass to the distance between B and C

Me find the measure to side c and the process to solve the problem you appreciate it : )

In the following diagram it is given that dec,ab || dc, ad || eb, and ad is congruent to bc. a)why isn't abc a parallelogram even though it has a pair of parallel sides and a pair of congruent sides b)explain why be must be congruent to bc. further explain what type of triangle this makes triangle abc and what it tells you about angle 1 and angle 2c) finally why must angle 3 be congruent to angle 1? further, explain why we know that angle 3 is congruent to angle 2

In a test for esp (extrasensory perception), the experimenter looks at cards that are hidden from the subject. each card contains either a star, a circle, a wave, a cross or a square.(five shapes) as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. when the esp study described above discovers a subject whose performance appears to be better than guessing, the study continues at greater length. the experimenter looks at many cards bearing one of five shapes (star, square, circle, wave, and cross) in an order determined by random numbers. the subject cannot see the experimenter as he looks at each card in turn, in order to avoid any possible nonverbal clues. the answers of a subject who does not have esp should be independent observations, each with probability 1/5 of success. we record 1000 attempts. which of the following assumptions must be met in order to solve this problem? it's reasonable to assume normality 0.8(1000), 0.2(1000)%30 approximately normal 0.8(1000), 0.2(1000)% 10 approximately normal srs it is reasonable to assume the total number of cards is over 10,000 it is reasonable to assume the total number of cards is over 1000