10 points. Plz help, I'll mark brainliest. Part A
Since triangle 2 is a right triangle, write an equation applying the Pythagorean Theorem to the triangle.

Part B
Since the equations for both triangles have a2 + b2, you can think of the two equations for c2 and n2 as a system of equations. Substitute what a2 + b2 equals in the first equation for a2 + b2 in the second equation. After you substitute, what equation do you get?

Part C
Now, take the square root of both sides of the equation from part B and write the resulting equation.

Part D
Is there any way for this equation to be true? How?

Part E
What does this show about the relationship between the two triangles?

Part F
Does this mean that triangle 1 is a right triangle? Why or why not?

3,000,540

step-by-step explanation:

17

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

i think its doubled. let me know

step-by-step explanation: