Evaluate the equation h=−4.9t2+24t+7 for the following values of t. t = 0
t = 1
t = 2
t = 3
t = 4
t = 5

t=0 => h = 7

t=1 => h = -5

t=2 => h = -89

t=3 => h = -245

t=4 => h = -473

t=5 => h = -773

Step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v