2. What is the solution of the equation x2 + 6x + 6 = 0?

(x+3)^2=3

Step-by-step explanation:

First, you'll need to set this up.

(x^2+6x            )+6         =0

We are going to solve the blank spaces now. The number next to the x is a 6. We need to find half of that which is 3. Next we need to square it which is 9. Here is how it looks like now.

(x^2+6x+9 )+6         =0

Next we need to find the next blank space, that will just be the same number of the first blank, just negative which would be -9.

(x^2+6x+9 )+6-9=0

Now we need to simplify! First we need to find the square of (x^2+6x+9). If you don't know how to do this, just say so in the comments! Anyways the square of this is (x+3)(x+3) or (x+3)^2.

So the equation now is (x+3)^2+6-9=0

Now, you need to do +6-9 which is -3.

The equation now is (x+3)^2-3=0

Now we need to put the -3 to the other side so (x+3)^2 can be isolated. So...

(x+3)^2-3=0

          +3 +3

(x+3)^2=3

THAT IS THE FINAL ANSWER! :) Hopefully this helped and making this answer "The Brainliest" would really help! Thank you and have a great day!

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1